pylint-errors
R1723 (no-else-break)
Problematic code:
def foo(n: int, stop: int):
for i in range(n):
if i == stop:
break
else:
yield i
Correct code:
def foo(n: int, stop: int):
for i in range(n):
if i == stop:
break
yield i
Rationale:
Used in order to highlight an unnecessary block of code following an if
containing a break statement. As such, it will warn when it encounters an
else following a chain of ifs, all of them containing a break statement.